Base | Representation |
---|---|
bin | 1100001101011101010101… |
… | …1110011011110101010011 |
3 | 1202112110012000201002001122 |
4 | 3003113111132123311103 |
5 | 3224430111201402311 |
6 | 44315304515552455 |
7 | 2553643536614264 |
oct | 303272536336523 |
9 | 52473160632048 |
10 | 13425354325331 |
11 | 430672a577a73 |
12 | 1609b0bbbb72b |
13 | 76500c06bb10 |
14 | 345b0d64696b |
15 | 184356de30db |
hex | c35d579bd53 |
13425354325331 has 32 divisors (see below), whose sum is σ = 14667178186752. Its totient is φ = 12214628046720.
The previous prime is 13425354325247. The next prime is 13425354325343. The reversal of 13425354325331 is 13352345352431.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13425354325331 is a prime.
It is a super-2 number, since 2×134253543253312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13425354325531) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 367568036 + ... + 367604558.
It is an arithmetic number, because the mean of its divisors is an integer number (458349318336).
Almost surely, 213425354325331 is an apocalyptic number.
13425354325331 is a deficient number, since it is larger than the sum of its proper divisors (1241823861421).
13425354325331 is a wasteful number, since it uses less digits than its factorization.
13425354325331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37923.
The product of its digits is 1944000, while the sum is 44.
Adding to 13425354325331 its reverse (13352345352431), we get a palindrome (26777699677762).
The spelling of 13425354325331 in words is "thirteen trillion, four hundred twenty-five billion, three hundred fifty-four million, three hundred twenty-five thousand, three hundred thirty-one".
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