Base | Representation |
---|---|
bin | 1100001101011101100001… |
… | …0000100111010110001011 |
3 | 1202112110022021121010110220 |
4 | 3003113120100213112023 |
5 | 3224430210131042443 |
6 | 44315313305041123 |
7 | 2553644644623441 |
oct | 303273020472613 |
9 | 52473267533426 |
10 | 13425401034123 |
11 | 430675397aa81 |
12 | 1609b237861a3 |
13 | 765018944160 |
14 | 345b15924b91 |
15 | 18435b06ca83 |
hex | c35d842758b |
13425401034123 has 64 divisors (see below), whose sum is σ = 19685682035712. Its totient is φ = 8088179950080.
The previous prime is 13425401034121. The next prime is 13425401034137. The reversal of 13425401034123 is 32143010452431.
It is not a de Polignac number, because 13425401034123 - 21 = 13425401034121 is a prime.
It is a super-3 number, since 3×134254010341233 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (13425401034121) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 742669561 + ... + 742687637.
It is an arithmetic number, because the mean of its divisors is an integer number (307588781808).
Almost surely, 213425401034123 is an apocalyptic number.
13425401034123 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13425401034123 is a deficient number, since it is larger than the sum of its proper divisors (6260281001589).
13425401034123 is a wasteful number, since it uses less digits than its factorization.
13425401034123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19604.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 13425401034123 its reverse (32143010452431), we get a palindrome (45568411486554).
The spelling of 13425401034123 in words is "thirteen trillion, four hundred twenty-five billion, four hundred one million, thirty-four thousand, one hundred twenty-three".
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