Base | Representation |
---|---|
bin | 1100001101011101101000… |
… | …0111001010100000110001 |
3 | 1202112110101110002000011000 |
4 | 3003113122013022200301 |
5 | 3224430241110024103 |
6 | 44315320335112213 |
7 | 2553645503026146 |
oct | 303273207124061 |
9 | 52473343060130 |
10 | 13425432111153 |
11 | 430676a476677 |
12 | 1609b32072669 |
13 | 76502220542a |
14 | 345b19ad43cd |
15 | 18435db5aaa3 |
hex | c35da1ca831 |
13425432111153 has 32 divisors (see below), whose sum is σ = 19935248486400. Its totient is φ = 8929719702288.
The previous prime is 13425432111071. The next prime is 13425432111173. The reversal of 13425432111153 is 35111123452431.
13425432111153 is a `hidden beast` number, since 1 + 3 + 42 + 543 + 2 + 11 + 11 + 53 = 666.
It is not a de Polignac number, because 13425432111153 - 213 = 13425432102961 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13425432111173) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 95024518 + ... + 95165696.
It is an arithmetic number, because the mean of its divisors is an integer number (622976515200).
Almost surely, 213425432111153 is an apocalyptic number.
It is an amenable number.
13425432111153 is a deficient number, since it is larger than the sum of its proper divisors (6509816375247).
13425432111153 is a wasteful number, since it uses less digits than its factorization.
13425432111153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 149258 (or 149252 counting only the distinct ones).
The product of its digits is 43200, while the sum is 36.
Adding to 13425432111153 its reverse (35111123452431), we get a palindrome (48536555563584).
The spelling of 13425432111153 in words is "thirteen trillion, four hundred twenty-five billion, four hundred thirty-two million, one hundred eleven thousand, one hundred fifty-three".
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