Base | Representation |
---|---|
bin | 1100001101011101111001… |
… | …0110000101001110110000 |
3 | 1202112110120101201011102211 |
4 | 3003113132112011032300 |
5 | 3224430412300134134 |
6 | 44315331353221504 |
7 | 2553650324466601 |
oct | 303273626051660 |
9 | 52473511634384 |
10 | 13425503130544 |
11 | 43067a657358a |
12 | 1609b51a01894 |
13 | 765033b3cc3b |
14 | 345b252ddda8 |
15 | 184364ed8764 |
hex | c35de5853b0 |
13425503130544 has 80 divisors (see below), whose sum is σ = 26300408853600. Its totient is φ = 6638717173760.
The previous prime is 13425503130527. The next prime is 13425503130553. The reversal of 13425503130544 is 44503130552431.
13425503130544 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13425503130497 and 13425503130506.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1973464647 + ... + 1973471449.
It is an arithmetic number, because the mean of its divisors is an integer number (328755110670).
Almost surely, 213425503130544 is an apocalyptic number.
It is an amenable number.
13425503130544 is a deficient number, since it is larger than the sum of its proper divisors (12874905723056).
13425503130544 is a wasteful number, since it uses less digits than its factorization.
13425503130544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10438 (or 10432 counting only the distinct ones).
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 13425503130544 its reverse (44503130552431), we get a palindrome (57928633682975).
The spelling of 13425503130544 in words is "thirteen trillion, four hundred twenty-five billion, five hundred three million, one hundred thirty thousand, five hundred forty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •