Base | Representation |
---|---|
bin | 1100001101011110011100… |
… | …1011110011100011011111 |
3 | 1202112110221201202122022021 |
4 | 3003113213023303203133 |
5 | 3224431213231303042 |
6 | 44315354212001011 |
7 | 2553654105152410 |
oct | 303274713634337 |
9 | 52473851678267 |
10 | 13425651431647 |
11 | 4306872255384 |
12 | 1609b93600167 |
13 | 765058795780 |
14 | 345b3aca5807 |
15 | 18437302e867 |
hex | c35e72f38df |
13425651431647 has 128 divisors (see below), whose sum is σ = 18332476968960. Its totient is φ = 9539284930560.
The previous prime is 13425651431639. The next prime is 13425651431669. The reversal of 13425651431647 is 74613415652431.
It is not a de Polignac number, because 13425651431647 - 23 = 13425651431639 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13425651431594 and 13425651431603.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13425651431627) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 763984353 + ... + 764001925.
It is an arithmetic number, because the mean of its divisors is an integer number (143222476320).
Almost surely, 213425651431647 is an apocalyptic number.
13425651431647 is a deficient number, since it is larger than the sum of its proper divisors (4906825537313).
13425651431647 is a wasteful number, since it uses less digits than its factorization.
13425651431647 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17993.
The product of its digits is 7257600, while the sum is 52.
The spelling of 13425651431647 in words is "thirteen trillion, four hundred twenty-five billion, six hundred fifty-one million, four hundred thirty-one thousand, six hundred forty-seven".
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