Base | Representation |
---|---|
bin | 10011100010011001011… |
… | …101101110000101110101 |
3 | 11202100111102020100221011 |
4 | 103202121131232011311 |
5 | 133444123223020430 |
6 | 2504441201552221 |
7 | 165666663651541 |
oct | 23423135560565 |
9 | 4670442210834 |
10 | 1342604501365 |
11 | 47843926a6a6 |
12 | 198257645671 |
13 | 997b793776a |
14 | 48da7a0aa21 |
15 | 24dce3cb22a |
hex | 1389976e175 |
1342604501365 has 16 divisors (see below), whose sum is σ = 1726611481728. Its totient is φ = 999617167296.
The previous prime is 1342604501339. The next prime is 1342604501369. The reversal of 1342604501365 is 5631054062431.
It is a cyclic number.
It is not a de Polignac number, because 1342604501365 - 27 = 1342604501237 is a prime.
It is a super-4 number, since 4×13426045013654 (a number of 50 digits) contains 4444 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1342604501369) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 157763607 + ... + 157772116.
It is an arithmetic number, because the mean of its divisors is an integer number (107913217608).
Almost surely, 21342604501365 is an apocalyptic number.
It is an amenable number.
1342604501365 is a deficient number, since it is larger than the sum of its proper divisors (384006980363).
1342604501365 is a wasteful number, since it uses less digits than its factorization.
1342604501365 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 315535788.
The product of its (nonzero) digits is 259200, while the sum is 40.
Adding to 1342604501365 its reverse (5631054062431), we get a palindrome (6973658563796).
The spelling of 1342604501365 in words is "one trillion, three hundred forty-two billion, six hundred four million, five hundred one thousand, three hundred sixty-five".
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