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13426537 = 47463617
BaseRepresentation
bin110011001101…
…111101101001
3221021010202011
4303031331221
511414122122
61155435521
7222060265
oct63157551
927233664
1013426537
117640613
1245b5ba1
132a213c7
141ad70a5
1512a3377
hexccdf69

13426537 has 8 divisors (see below), whose sum is σ = 13764096. Its totient is φ = 13091232.

The previous prime is 13426531. The next prime is 13426541. The reversal of 13426537 is 73562431.

13426537 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13426537 - 23 = 13426529 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13426499 and 13426508.

It is not an unprimeable number, because it can be changed into a prime (13426531) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21453 + ... + 22069.

It is an arithmetic number, because the mean of its divisors is an integer number (1720512).

Almost surely, 213426537 is an apocalyptic number.

It is an amenable number.

13426537 is a deficient number, since it is larger than the sum of its proper divisors (337559).

13426537 is an equidigital number, since it uses as much as digits as its factorization.

13426537 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1127.

The product of its digits is 15120, while the sum is 31.

The square root of 13426537 is about 3664.2239287467. The cubic root of 13426537 is about 237.6774636699.

Adding to 13426537 its reverse (73562431), we get a palindrome (86988968).

The spelling of 13426537 in words is "thirteen million, four hundred twenty-six thousand, five hundred thirty-seven".

Divisors: 1 47 463 617 21761 28999 285671 13426537