Base | Representation |
---|---|
bin | 10011100010011100100… |
… | …000011010101110110111 |
3 | 11202100121222021101222120 |
4 | 103202130200122232313 |
5 | 133444224304241101 |
6 | 2504450223531023 |
7 | 166001153533632 |
oct | 23423440325667 |
9 | 4670558241876 |
10 | 1342655540151 |
11 | 47846505a912 |
12 | 198270759a73 |
13 | 997c5397923 |
14 | 48db06d4c19 |
15 | 24dd3b0db36 |
hex | 1389c81abb7 |
1342655540151 has 4 divisors (see below), whose sum is σ = 1790207386872. Its totient is φ = 895103693432.
The previous prime is 1342655540089. The next prime is 1342655540173. The reversal of 1342655540151 is 1510455562431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1342655540151 - 26 = 1342655540087 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1342655550151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223775923356 + ... + 223775923361.
It is an arithmetic number, because the mean of its divisors is an integer number (447551846718).
Almost surely, 21342655540151 is an apocalyptic number.
1342655540151 is a deficient number, since it is larger than the sum of its proper divisors (447551846721).
1342655540151 is an equidigital number, since it uses as much as digits as its factorization.
1342655540151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 447551846720.
The product of its (nonzero) digits is 360000, while the sum is 42.
The spelling of 1342655540151 in words is "one trillion, three hundred forty-two billion, six hundred fifty-five million, five hundred forty thousand, one hundred fifty-one".
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