1342656041 has 4 divisors (see below), whose sum is σ = 1344316500. Its totient is φ = 1340995584.

The previous prime is 1342656023. The next prime is 1342656043. The reversal of 1342656041 is 1406562431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1406562431 = 4211 ⋅334021.

It can be written as a sum of positive squares in 2 ways, for example, as 819161641 + 523494400 = 28621^2 + 22880^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1342656041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1342655989 and 1342656007.

It is not an unprimeable number, because it can be changed into a prime (1342656043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 829016 + ... + 830633.

It is an arithmetic number, because the mean of its divisors is an integer number (336079125).

Almost surely, 2^1342656041 is an apocalyptic number.

It is an amenable number.

1342656041 is a deficient number, since it is larger than the sum of its proper divisors (1660459).

1342656041 is an equidigital number, since it uses as much as digits as its factorization.

1342656041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1660458.

The product of its (nonzero) digits is 17280, while the sum is 32.

The square root of 1342656041 is about 36642.2712314616. The cubic root of 1342656041 is about 1103.2017025379.

The spelling of 1342656041 in words is "one billion, three hundred forty-two million, six hundred fifty-six thousand, forty-one".