Base | Representation |
---|---|
bin | 111110100001011011… |
… | …0110100101101100001 |
3 | 110211120012111221000012 |
4 | 1331002312310231201 |
5 | 4144434001412423 |
6 | 141403014534305 |
7 | 12462141141503 |
oct | 1750266645541 |
9 | 424505457005 |
10 | 134265654113 |
11 | 51a3a509208 |
12 | 22031367395 |
13 | c879859c16 |
14 | 66d9c11d73 |
15 | 375c5b1078 |
hex | 1f42db4b61 |
134265654113 has 4 divisors (see below), whose sum is σ = 134266695108. Its totient is φ = 134264613120.
The previous prime is 134265654071. The next prime is 134265654161. The reversal of 134265654113 is 311456562431.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It can be written as a sum of positive squares in 2 ways, for example, as 132018135649 + 2247518464 = 363343^2 + 47408^2 .
It is a cyclic number.
It is not a de Polignac number, because 134265654113 - 222 = 134261459809 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134265654613) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 294248 + ... + 595913.
It is an arithmetic number, because the mean of its divisors is an integer number (33566673777).
Almost surely, 2134265654113 is an apocalyptic number.
It is an amenable number.
134265654113 is a deficient number, since it is larger than the sum of its proper divisors (1040995).
134265654113 is an equidigital number, since it uses as much as digits as its factorization.
134265654113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1040994.
The product of its digits is 259200, while the sum is 41.
The spelling of 134265654113 in words is "one hundred thirty-four billion, two hundred sixty-five million, six hundred fifty-four thousand, one hundred thirteen".
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