Base | Representation |
---|---|
bin | 111110100001011011… |
… | …0110100101100110111 |
3 | 110211120012111220221122 |
4 | 1331002312310230313 |
5 | 4144434001412241 |
6 | 141403014534155 |
7 | 12462141141413 |
oct | 1750266645467 |
9 | 424505456848 |
10 | 134265654071 |
11 | 51a3a50917a |
12 | 2203136735b |
13 | c879859bb3 |
14 | 66d9c11d43 |
15 | 375c5b104b |
hex | 1f42db4b37 |
134265654071 has 2 divisors, whose sum is σ = 134265654072. Its totient is φ = 134265654070.
The previous prime is 134265654001. The next prime is 134265654161. The reversal of 134265654071 is 170456562431.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134265654071 is a prime.
It is a super-2 number, since 2×1342656540712 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134265654001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67132827035 + 67132827036.
It is an arithmetic number, because the mean of its divisors is an integer number (67132827036).
Almost surely, 2134265654071 is an apocalyptic number.
134265654071 is a deficient number, since it is larger than the sum of its proper divisors (1).
134265654071 is an equidigital number, since it uses as much as digits as its factorization.
134265654071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 604800, while the sum is 44.
The spelling of 134265654071 in words is "one hundred thirty-four billion, two hundred sixty-five million, six hundred fifty-four thousand, seventy-one".
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