Base | Representation |
---|---|
bin | 11110100010010101110001… |
… | …010000001010100011010011 |
3 | 122121112001221210200112102121 |
4 | 132202111301100022203103 |
5 | 120100342411001112210 |
6 | 1153345045012355111 |
7 | 40200641511213304 |
oct | 3642256120124323 |
9 | 577461853615377 |
10 | 134301232441555 |
11 | 3987991853a733 |
12 | 1309058b015a97 |
13 | 59c272362207a |
14 | 25243001b67ab |
15 | 107d73b00a6da |
hex | 7a257140a8d3 |
134301232441555 has 32 divisors (see below), whose sum is σ = 165173213709504. Its totient is φ = 104774525485056.
The previous prime is 134301232441511. The next prime is 134301232441583. The reversal of 134301232441555 is 555144232103431.
It is a cyclic number.
It is not a de Polignac number, because 134301232441555 - 29 = 134301232441043 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1403059557 + ... + 1403155273.
It is an arithmetic number, because the mean of its divisors is an integer number (5161662928422).
Almost surely, 2134301232441555 is an apocalyptic number.
134301232441555 is a deficient number, since it is larger than the sum of its proper divisors (30871981267949).
134301232441555 is an equidigital number, since it uses as much as digits as its factorization.
134301232441555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 106135.
The product of its (nonzero) digits is 864000, while the sum is 43.
Adding to 134301232441555 its reverse (555144232103431), we get a palindrome (689445464544986).
The spelling of 134301232441555 in words is "one hundred thirty-four trillion, three hundred one billion, two hundred thirty-two million, four hundred forty-one thousand, five hundred fifty-five".
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