Base | Representation |
---|---|
bin | 10011100010110010110… |
… | …110100000110111100001 |
3 | 11202101121002200211211021 |
4 | 103202302312200313201 |
5 | 134001011242244301 |
6 | 2504551335045441 |
7 | 166013355210514 |
oct | 23426266406741 |
9 | 4671532624737 |
10 | 1343030431201 |
11 | 478637736028 |
12 | 198356210881 |
13 | 99854c57554 |
14 | 49008400d7b |
15 | 24e069b28a1 |
hex | 138b2da0de1 |
1343030431201 has 4 divisors (see below), whose sum is σ = 1343051424304. Its totient is φ = 1343009438100.
The previous prime is 1343030431199. The next prime is 1343030431219. The reversal of 1343030431201 is 1021340303431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1343030431201 - 21 = 1343030431199 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1343036431201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10400295 + ... + 10528636.
It is an arithmetic number, because the mean of its divisors is an integer number (335762856076).
Almost surely, 21343030431201 is an apocalyptic number.
It is an amenable number.
1343030431201 is a deficient number, since it is larger than the sum of its proper divisors (20993103).
1343030431201 is an equidigital number, since it uses as much as digits as its factorization.
1343030431201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20993102.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1343030431201 its reverse (1021340303431), we get a palindrome (2364370734632).
The spelling of 1343030431201 in words is "one trillion, three hundred forty-three billion, thirty million, four hundred thirty-one thousand, two hundred one".
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