1343111340042 has 40 divisors (see below), whose sum is σ = 3010686989376. Its totient is φ = 447536768328.

The previous prime is 1343111340023. The next prime is 1343111340047. The reversal of 1343111340042 is 2400431113431.

1343111340042 is a `hidden beast` number, since 1 + 3 + 4 + 311 + 1 + 340 + 0 + 4 + 2 = 666.

It is a super-4 number, since 4×1343111340042⁴ (a number of 50 digits) contains 4444 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 1343111339988 and 1343111340015.

It is not an unprimeable number, because it can be changed into a prime (1343111340047) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 1110418 + ... + 1979709.

Almost surely, 2^{1343111340042} is an apocalyptic number.

1343111340042 is an abundant number, since it is smaller than the sum of its proper divisors (1667575649334).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1343111340042 is a wasteful number, since it uses less digits than its factorization.

1343111340042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3092824 (or 3092815 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 1343111340042 its reverse (2400431113431), we get a palindrome (3743542453473).

The spelling of 1343111340042 in words is "one trillion, three hundred forty-three billion, one hundred eleven million, three hundred forty thousand, forty-two".