1343113414413 has 4 divisors (see below), whose sum is σ = 1790817885888. Its totient is φ = 895408942940.

The previous prime is 1343113414399. The next prime is 1343113414417. The reversal of 1343113414413 is 3144143113431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1343113414413 - 2⁵ = 1343113414381 is a prime.

It is a super-2 number, since 2×1343113414413² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1343113414417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223852235733 + ... + 223852235738.

It is an arithmetic number, because the mean of its divisors is an integer number (447704471472).

Almost surely, 2^{1343113414413} is an apocalyptic number.

It is an amenable number.

1343113414413 is a deficient number, since it is larger than the sum of its proper divisors (447704471475).

1343113414413 is an equidigital number, since it uses as much as digits as its factorization.

1343113414413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 447704471474.

The product of its digits is 20736, while the sum is 33.

Adding to 1343113414413 its reverse (3144143113431), we get a palindrome (4487256527844).

The spelling of 1343113414413 in words is "one trillion, three hundred forty-three billion, one hundred thirteen million, four hundred fourteen thousand, four hundred thirteen".