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1343124443131 = 4664832879257
BaseRepresentation
bin10011100010111000011…
…101001000111111111011
311202101211122121010221121
4103202320131020333323
5134001204324140011
62505004534050111
7166015606253002
oct23427035107773
94671748533847
101343124443131
11478685807639
121983817a9937
139986b582603
1449016ab3c39
1524e0ed82e71
hex138b8748ffb

1343124443131 has 4 divisors (see below), whose sum is σ = 1343127788872. Its totient is φ = 1343121097392.

The previous prime is 1343124443081. The next prime is 1343124443251. The reversal of 1343124443131 is 1313444213431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1343124443131 - 29 = 1343124442619 is a prime.

It is a super-2 number, since 2×13431244431312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1343124843131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 973146 + ... + 1906111.

It is an arithmetic number, because the mean of its divisors is an integer number (335781947218).

Almost surely, 21343124443131 is an apocalyptic number.

1343124443131 is a deficient number, since it is larger than the sum of its proper divisors (3345741).

1343124443131 is an equidigital number, since it uses as much as digits as its factorization.

1343124443131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3345740.

The product of its digits is 41472, while the sum is 34.

Adding to 1343124443131 its reverse (1313444213431), we get a palindrome (2656568656562).

The spelling of 1343124443131 in words is "one trillion, three hundred forty-three billion, one hundred twenty-four million, four hundred forty-three thousand, one hundred thirty-one".

Divisors: 1 466483 2879257 1343124443131