Base | Representation |
---|---|
bin | 11001000001001001… |
… | …10011100111100011 |
3 | 1021200001120220101021 |
4 | 30200210303213203 |
5 | 210001420441121 |
6 | 10100441550311 |
7 | 653562125002 |
oct | 144044634743 |
9 | 37601526337 |
10 | 13431421411 |
11 | 5772761781 |
12 | 272a1a5397 |
13 | 1360895245 |
14 | 915b8cc39 |
15 | 539270641 |
hex | 3209339e3 |
13431421411 has 4 divisors (see below), whose sum is σ = 13431673800. Its totient is φ = 13431169024.
The previous prime is 13431421373. The next prime is 13431421441. The reversal of 13431421411 is 11412413431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13431421411 - 215 = 13431388643 is a prime.
It is a super-2 number, since 2×134314214112 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13431421441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11806 + ... + 164323.
It is an arithmetic number, because the mean of its divisors is an integer number (3357918450).
Almost surely, 213431421411 is an apocalyptic number.
13431421411 is a deficient number, since it is larger than the sum of its proper divisors (252389).
13431421411 is an equidigital number, since it uses as much as digits as its factorization.
13431421411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 252388.
The product of its digits is 1152, while the sum is 25.
Adding to 13431421411 its reverse (11412413431), we get a palindrome (24843834842).
The spelling of 13431421411 in words is "thirteen billion, four hundred thirty-one million, four hundred twenty-one thousand, four hundred eleven".
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