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1343143232111 = 6076122105351
BaseRepresentation
bin10011100010111001100…
…100110100001001101111
311202101212221221201120202
4103202321210310021233
5134001224131411421
62505010444504115
7166016225046242
oct23427144641157
94671787851522
101343143232111
1147869538001a
12198387b4b03b
1399872430755
14490193a5259
1524e1184510b
hex138b993426f

1343143232111 has 4 divisors (see below), whose sum is σ = 1343165398224. Its totient is φ = 1343121066000.

The previous prime is 1343143232087. The next prime is 1343143232131. The reversal of 1343143232111 is 1112323413431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1343143232111 - 218 = 1343142969967 is a prime.

It is a super-3 number, since 3×13431432321113 (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1343143232131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10991915 + ... + 11113436.

It is an arithmetic number, because the mean of its divisors is an integer number (335791349556).

Almost surely, 21343143232111 is an apocalyptic number.

1343143232111 is a deficient number, since it is larger than the sum of its proper divisors (22166113).

1343143232111 is an equidigital number, since it uses as much as digits as its factorization.

1343143232111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22166112.

The product of its digits is 5184, while the sum is 29.

Adding to 1343143232111 its reverse (1112323413431), we get a palindrome (2455466645542).

The spelling of 1343143232111 in words is "one trillion, three hundred forty-three billion, one hundred forty-three million, two hundred thirty-two thousand, one hundred eleven".

Divisors: 1 60761 22105351 1343143232111