Base | Representation |
---|---|
bin | 1100001101110100010001… |
… | …1010001101001111000011 |
3 | 1202120001002001112212200220 |
4 | 3003131010122031033003 |
5 | 3230030213134031420 |
6 | 44322203431114123 |
7 | 2554252231063005 |
oct | 303350432151703 |
9 | 52501061485626 |
10 | 13431510455235 |
11 | 43092a9547534 |
12 | 160b149812943 |
13 | 7657805a1932 |
14 | 346135098375 |
15 | 1845b75bb840 |
hex | c374468d3c3 |
13431510455235 has 16 divisors (see below), whose sum is σ = 22424782673664. Its totient is φ = 6852016927712.
The previous prime is 13431510455201. The next prime is 13431510455239. The reversal of 13431510455235 is 53255401513431.
It is a cyclic number.
It is not a de Polignac number, because 13431510455235 - 26 = 13431510455171 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13431510455239) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19465956837 + ... + 19465957526.
It is an arithmetic number, because the mean of its divisors is an integer number (1401548917104).
Almost surely, 213431510455235 is an apocalyptic number.
13431510455235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13431510455235 is a deficient number, since it is larger than the sum of its proper divisors (8993272218429).
13431510455235 is a wasteful number, since it uses less digits than its factorization.
13431510455235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38931914394.
The product of its (nonzero) digits is 540000, while the sum is 42.
Adding to 13431510455235 its reverse (53255401513431), we get a palindrome (66686911968666).
The spelling of 13431510455235 in words is "thirteen trillion, four hundred thirty-one billion, five hundred ten million, four hundred fifty-five thousand, two hundred thirty-five".
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