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1343152115313 = 3447717371771
BaseRepresentation
bin10011100010111010000…
…110101100111001110001
311202101220120200001001020
4103202322012230321301
5134001233420142223
62505011403130053
7166016363414631
oct23427206547161
94671816601036
101343152115313
1147869a398108
1219838ab13929
1399874220b98
144901a6386c1
1524e124ec1e3
hex138ba1ace71

1343152115313 has 4 divisors (see below), whose sum is σ = 1790869487088. Its totient is φ = 895434743540.

The previous prime is 1343152115257. The next prime is 1343152115329. The reversal of 1343152115313 is 3135112513431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1343152115313 - 232 = 1338857148017 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1343152114313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223858685883 + ... + 223858685888.

It is an arithmetic number, because the mean of its divisors is an integer number (447717371772).

Almost surely, 21343152115313 is an apocalyptic number.

It is an amenable number.

1343152115313 is a deficient number, since it is larger than the sum of its proper divisors (447717371775).

1343152115313 is an equidigital number, since it uses as much as digits as its factorization.

1343152115313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 447717371774.

The product of its digits is 16200, while the sum is 33.

Adding to 1343152115313 its reverse (3135112513431), we get a palindrome (4478264628744).

The spelling of 1343152115313 in words is "one trillion, three hundred forty-three billion, one hundred fifty-two million, one hundred fifteen thousand, three hundred thirteen".

Divisors: 1 3 447717371771 1343152115313