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1338857148017 is a prime number
BaseRepresentation
bin10011011110111010000…
…110101100111001110001
311201222211020221002112102
4103132322012230321301
5133413434412214032
62503021255110145
7165505061662244
oct23367206547161
94658736832472
101338857148017
11476895a57664
12197590672355
139933b47430c
1448b3006125b
1524c6040e362
hex137ba1ace71

1338857148017 has 2 divisors, whose sum is σ = 1338857148018. Its totient is φ = 1338857148016.

The previous prime is 1338857147989. The next prime is 1338857148023. The reversal of 1338857148017 is 7108417588331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1020485856481 + 318371291536 = 1010191^2 + 564244^2 .

It is an emirp because it is prime and its reverse (7108417588331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1338857148017 - 234 = 1321677278833 is a prime.

It is not a weakly prime, because it can be changed into another prime (1338857148047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 669428574008 + 669428574009.

It is an arithmetic number, because the mean of its divisors is an integer number (669428574009).

Almost surely, 21338857148017 is an apocalyptic number.

It is an amenable number.

1338857148017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1338857148017 is an equidigital number, since it uses as much as digits as its factorization.

1338857148017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4515840, while the sum is 56.

The spelling of 1338857148017 in words is "one trillion, three hundred thirty-eight billion, eight hundred fifty-seven million, one hundred forty-eight thousand, seventeen".