13432402550031 has 8 divisors (see below), whose sum is σ = 18346696166064. Its totient is φ = 8736521983680.

The previous prime is 13432402549999. The next prime is 13432402550069. The reversal of 13432402550031 is 13005520423431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13432402550031 - 2⁵ = 13432402549999 is a prime.

It is a super-2 number, since 2×13432402550031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13432402549974 and 13432402550001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13432403550031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 54603262276 + ... + 54603262521.

It is an arithmetic number, because the mean of its divisors is an integer number (2293337020758).

Almost surely, 2^{13432402550031} is an apocalyptic number.

13432402550031 is a deficient number, since it is larger than the sum of its proper divisors (4914293616033).

13432402550031 is a wasteful number, since it uses less digits than its factorization.

13432402550031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109206524841.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 13432402550031 its reverse (13005520423431), we get a palindrome (26437922973462).

The spelling of 13432402550031 in words is "thirteen trillion, four hundred thirty-two billion, four hundred two million, five hundred fifty thousand, thirty-one".