Base | Representation |
---|---|
bin | 1100001101110111100110… |
… | …0101010001110101011001 |
3 | 1202120010101020011222210122 |
4 | 3003131321211101311121 |
5 | 3230034030023100410 |
6 | 44322432135523025 |
7 | 2554313312545460 |
oct | 303357145216531 |
9 | 52503336158718 |
10 | 13432402550105 |
11 | 430971706a620 |
12 | 160b358529475 |
13 | 76589335b116 |
14 | 3461bb7579d7 |
15 | 18461aa85e55 |
hex | c3779951d59 |
13432402550105 has 64 divisors (see below), whose sum is σ = 20373845760000. Its totient is φ = 8257814853120.
The previous prime is 13432402550087. The next prime is 13432402550107. The reversal of 13432402550105 is 50105520423431.
It is not a de Polignac number, because 13432402550105 - 216 = 13432402484569 is a prime.
It is a super-2 number, since 2×134324025501052 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is not an unprimeable number, because it can be changed into a prime (13432402550107) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 317537246 + ... + 317579544.
It is an arithmetic number, because the mean of its divisors is an integer number (318341340000).
Almost surely, 213432402550105 is an apocalyptic number.
It is an amenable number.
13432402550105 is a deficient number, since it is larger than the sum of its proper divisors (6941443209895).
13432402550105 is a wasteful number, since it uses less digits than its factorization.
13432402550105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53694.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 13432402550105 its reverse (50105520423431), we get a palindrome (63537922973536).
The spelling of 13432402550105 in words is "thirteen trillion, four hundred thirty-two billion, four hundred two million, five hundred fifty thousand, one hundred five".
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