1343310300331 has 4 divisors (see below), whose sum is σ = 1389631345200. Its totient is φ = 1296989255464.

The previous prime is 1343310300307. The next prime is 1343310300373. The reversal of 1343310300331 is 1330030133431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1343310300331 - 2¹⁷ = 1343310169259 is a prime.

It is a super-2 number, since 2×1343310300331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1343310300296 and 1343310300305.

It is not an unprimeable number, because it can be changed into a prime (1343310307331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23160522391 + ... + 23160522448.

It is an arithmetic number, because the mean of its divisors is an integer number (347407836300).

Almost surely, 2^{1343310300331} is an apocalyptic number.

1343310300331 is a deficient number, since it is larger than the sum of its proper divisors (46321044869).

1343310300331 is an equidigital number, since it uses as much as digits as its factorization.

1343310300331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46321044868.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 1343310300331 its reverse (1330030133431), we get a palindrome (2673340433762).

The spelling of 1343310300331 in words is "one trillion, three hundred forty-three billion, three hundred ten million, three hundred thousand, three hundred thirty-one".