Search a number
-
+
13433104000 = 275323173211
BaseRepresentation
bin11001000001010110…
…01110011010000000
31021200011202101110101
430200223032122000
5210002333312000
610100542012144
7653612333341
oct144053163200
937604671411
1013433104000
115773700948
12272a877054
131361034064
149160aa0c8
155394a3e6a
hex320ace680

13433104000 has 256 divisors, whose sum is σ = 35217711360. Its totient is φ = 5085696000.

The previous prime is 13433103997. The next prime is 13433104021. The reversal of 13433104000 is 40133431.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 63663895 + ... + 63664105.

It is an arithmetic number, because the mean of its divisors is an integer number (137569185).

Almost surely, 213433104000 is an apocalyptic number.

13433104000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13433104000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17608855680).

13433104000 is an abundant number, since it is smaller than the sum of its proper divisors (21784607360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13433104000 is a wasteful number, since it uses less digits than its factorization.

13433104000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 436 (or 414 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 13433104000 its reverse (40133431), we get a palindrome (13473237431).

The spelling of 13433104000 in words is "thirteen billion, four hundred thirty-three million, one hundred four thousand".