Base | Representation |
---|---|
bin | 11110100010110001100111… |
… | …111000110101000011111001 |
3 | 122121121221011010020000110220 |
4 | 132202301213320311003321 |
5 | 120101340133331202340 |
6 | 1153410512425330253 |
7 | 40203050610135636 |
oct | 3642614770650371 |
9 | 577557133200426 |
10 | 134331140100345 |
11 | 39890575643411 |
12 | 13096337036989 |
13 | 59c54ab8256a6 |
14 | 252593a26518d |
15 | 107e3db993ed0 |
hex | 7a2c67e350f9 |
134331140100345 has 16 divisors (see below), whose sum is σ = 215059534414080. Its totient is φ = 71600037969024.
The previous prime is 134331140100329. The next prime is 134331140100379. The reversal of 134331140100345 is 543001041133431.
It is not a de Polignac number, because 134331140100345 - 24 = 134331140100329 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2702271265 + ... + 2702320974.
It is an arithmetic number, because the mean of its divisors is an integer number (13441220900880).
Almost surely, 2134331140100345 is an apocalyptic number.
134331140100345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
134331140100345 is a deficient number, since it is larger than the sum of its proper divisors (80728394313735).
134331140100345 is a wasteful number, since it uses less digits than its factorization.
134331140100345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5404593904.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 134331140100345 its reverse (543001041133431), we get a palindrome (677332181233776).
The spelling of 134331140100345 in words is "one hundred thirty-four trillion, three hundred thirty-one billion, one hundred forty million, one hundred thousand, three hundred forty-five".
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