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134331140100345 = 3516575404592239
BaseRepresentation
bin11110100010110001100111…
…111000110101000011111001
3122121121221011010020000110220
4132202301213320311003321
5120101340133331202340
61153410512425330253
740203050610135636
oct3642614770650371
9577557133200426
10134331140100345
1139890575643411
1213096337036989
1359c54ab8256a6
14252593a26518d
15107e3db993ed0
hex7a2c67e350f9

134331140100345 has 16 divisors (see below), whose sum is σ = 215059534414080. Its totient is φ = 71600037969024.

The previous prime is 134331140100329. The next prime is 134331140100379. The reversal of 134331140100345 is 543001041133431.

It is not a de Polignac number, because 134331140100345 - 24 = 134331140100329 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2702271265 + ... + 2702320974.

It is an arithmetic number, because the mean of its divisors is an integer number (13441220900880).

Almost surely, 2134331140100345 is an apocalyptic number.

134331140100345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

134331140100345 is a deficient number, since it is larger than the sum of its proper divisors (80728394313735).

134331140100345 is a wasteful number, since it uses less digits than its factorization.

134331140100345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5404593904.

The product of its (nonzero) digits is 25920, while the sum is 33.

Adding to 134331140100345 its reverse (543001041133431), we get a palindrome (677332181233776).

The spelling of 134331140100345 in words is "one hundred thirty-four trillion, three hundred thirty-one billion, one hundred forty million, one hundred thousand, three hundred forty-five".

Divisors: 1 3 5 15 1657 4971 8285 24855 5404592239 16213776717 27022961195 81068883585 8955409340023 26866228020069 44777046700115 134331140100345