Base | Representation |
---|---|
bin | 11110100010110001100111… |
… | …111000110101000100011011 |
3 | 122121121221011010020000112011 |
4 | 132202301213320311010123 |
5 | 120101340133331203004 |
6 | 1153410512425330351 |
7 | 40203050610136015 |
oct | 3642614770650433 |
9 | 577557133200464 |
10 | 134331140100379 |
11 | 39890575643442 |
12 | 130963370369b7 |
13 | 59c54ab825701 |
14 | 252593a2651b5 |
15 | 107e3db994004 |
hex | 7a2c67e3511b |
134331140100379 has 2 divisors, whose sum is σ = 134331140100380. Its totient is φ = 134331140100378.
The previous prime is 134331140100329. The next prime is 134331140100383. The reversal of 134331140100379 is 973001041133431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134331140100379 - 29 = 134331140099867 is a prime.
It is not a weakly prime, because it can be changed into another prime (134331140100329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67165570050189 + 67165570050190.
It is an arithmetic number, because the mean of its divisors is an integer number (67165570050190).
Almost surely, 2134331140100379 is an apocalyptic number.
134331140100379 is a deficient number, since it is larger than the sum of its proper divisors (1).
134331140100379 is an equidigital number, since it uses as much as digits as its factorization.
134331140100379 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81648, while the sum is 40.
The spelling of 134331140100379 in words is "one hundred thirty-four trillion, three hundred thirty-one billion, one hundred forty million, one hundred thousand, three hundred seventy-nine".
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