13433131144411 has 4 divisors (see below), whose sum is σ = 14654324884824. Its totient is φ = 12211937404000.

The previous prime is 13433131144399. The next prime is 13433131144421. The reversal of 13433131144411 is 11444113133431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13433131144411 - 2⁹ = 13433131143899 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13433131144421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 610596870190 + ... + 610596870211.

It is an arithmetic number, because the mean of its divisors is an integer number (3663581221206).

Almost surely, 2^{13433131144411} is an apocalyptic number.

13433131144411 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13433131144411 is a deficient number, since it is larger than the sum of its proper divisors (1221193740413).

13433131144411 is a wasteful number, since it uses less digits than its factorization.

13433131144411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1221193740412.

The product of its digits is 20736, while the sum is 34.

Adding to 13433131144411 its reverse (11444113133431), we get a palindrome (24877244277842).

The spelling of 13433131144411 in words is "thirteen trillion, four hundred thirty-three billion, one hundred thirty-one million, one hundred forty-four thousand, four hundred eleven".