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1343320231403 = 4149393663331
BaseRepresentation
bin10011100011000100001…
…000000000110111101011
311202102100022000012222002
4103203010020000313223
5134002104434401103
62505040210321215
7166023504366203
oct23430410006753
94672308005862
101343320231403
11478776283227
1219841728920b
139989ccc3867
1449034abb403
1524e22159488
hex138c4200deb

1343320231403 has 8 divisors (see below), whose sum is σ = 1376114073936. Its totient is φ = 1310527814400.

The previous prime is 1343320231369. The next prime is 1343320231441. The reversal of 1343320231403 is 3041320233431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1343320231403 - 218 = 1343319969259 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1343320231303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1693448 + ... + 2356778.

It is an arithmetic number, because the mean of its divisors is an integer number (172014259242).

Almost surely, 21343320231403 is an apocalyptic number.

1343320231403 is a deficient number, since it is larger than the sum of its proper divisors (32793842533).

1343320231403 is an equidigital number, since it uses as much as digits as its factorization.

1343320231403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 712765.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 1343320231403 its reverse (3041320233431), we get a palindrome (4384640464834).

The spelling of 1343320231403 in words is "one trillion, three hundred forty-three billion, three hundred twenty million, two hundred thirty-one thousand, four hundred three".

Divisors: 1 41 49393 663331 2025113 27196571 32763908083 1343320231403