Base | Representation |
---|---|
bin | 10011100011000100001… |
… | …000000000110111001001 |
3 | 11202102100022000012220211 |
4 | 103203010020000313021 |
5 | 134002104434400434 |
6 | 2505040210321121 |
7 | 166023504366124 |
oct | 23430410006711 |
9 | 4672308005824 |
10 | 1343320231369 |
11 | 4787762831a6 |
12 | 1984172891a1 |
13 | 9989ccc383c |
14 | 49034abb3bb |
15 | 24e22159464 |
hex | 138c4200dc9 |
1343320231369 has 2 divisors, whose sum is σ = 1343320231370. Its totient is φ = 1343320231368.
The previous prime is 1343320231343. The next prime is 1343320231441. The reversal of 1343320231369 is 9631320233431.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1286670519225 + 56649712144 = 1134315^2 + 238012^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1343320231369 is a prime.
It is a super-2 number, since 2×13433202313692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1343320231069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671660115684 + 671660115685.
It is an arithmetic number, because the mean of its divisors is an integer number (671660115685).
Almost surely, 21343320231369 is an apocalyptic number.
It is an amenable number.
1343320231369 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343320231369 is an equidigital number, since it uses as much as digits as its factorization.
1343320231369 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 209952, while the sum is 40.
The spelling of 1343320231369 in words is "one trillion, three hundred forty-three billion, three hundred twenty million, two hundred thirty-one thousand, three hundred sixty-nine".
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