13433240401 has 4 divisors (see below), whose sum is σ = 15352274752. Its totient is φ = 11514206052.

The previous prime is 13433240393. The next prime is 13433240519. The reversal of 13433240401 is 10404233431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13433240401 - 2³ = 13433240393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13433240101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 959517165 + ... + 959517178.

It is an arithmetic number, because the mean of its divisors is an integer number (3838068688).

Almost surely, 2^13433240401 is an apocalyptic number.

It is an amenable number.

13433240401 is a deficient number, since it is larger than the sum of its proper divisors (1919034351).

13433240401 is an equidigital number, since it uses as much as digits as its factorization.

13433240401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1919034350.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 13433240401 its reverse (10404233431), we get a palindrome (23837473832).

The spelling of 13433240401 in words is "thirteen billion, four hundred thirty-three million, two hundred forty thousand, four hundred one".