13433305420242 has 48 divisors (see below), whose sum is σ = 29297813132952. Its totient is φ = 4448194583040.

The previous prime is 13433305420217. The next prime is 13433305420273. The reversal of 13433305420242 is 24202450333431.

13433305420242 is a `hidden beast` number, since 1 + 3 + 43 + 3 + 30 + 542 + 0 + 2 + 42 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 11507624659521 + 1925680760721 = 3392289^2 + 1387689^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13433305420197 and 13433305420206.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11424648 + ... + 12545484.

Almost surely, 2^{13433305420242} is an apocalyptic number.

13433305420242 is an abundant number, since it is smaller than the sum of its proper divisors (15864507712710).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13433305420242 is a wasteful number, since it uses less digits than its factorization.

13433305420242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1125243 (or 1125240 counting only the distinct ones).

The product of its (nonzero) digits is 207360, while the sum is 36.

Adding to 13433305420242 its reverse (24202450333431), we get a palindrome (37635755753673).

The spelling of 13433305420242 in words is "thirteen trillion, four hundred thirty-three billion, three hundred five million, four hundred twenty thousand, two hundred forty-two".