Base | Representation |
---|---|
bin | 10011100011000101010… |
… | …100000000000100111101 |
3 | 11202102101200111020122200 |
4 | 103203011110000010331 |
5 | 134002130034313401 |
6 | 2505042201302113 |
7 | 166024135612134 |
oct | 23430524000475 |
9 | 4672350436580 |
10 | 1343340151101 |
11 | 478786549193 |
12 | 198421a94939 |
13 | 998a4179570 |
14 | 490375c491b |
15 | 24e23c91686 |
hex | 138c550013d |
1343340151101 has 12 divisors (see below), whose sum is σ = 2089640235228. Its totient is φ = 826670862144.
The previous prime is 1343340151081. The next prime is 1343340151117. The reversal of 1343340151101 is 1011510433431.
It can be written as a sum of positive squares in 2 ways, for example, as 733849222500 + 609490928601 = 856650^2 + 780699^2 .
It is not a de Polignac number, because 1343340151101 - 27 = 1343340150973 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1343340153101) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5740769760 + ... + 5740769993.
It is an arithmetic number, because the mean of its divisors is an integer number (174136686269).
Almost surely, 21343340151101 is an apocalyptic number.
It is an amenable number.
1343340151101 is a deficient number, since it is larger than the sum of its proper divisors (746300084127).
1343340151101 is a wasteful number, since it uses less digits than its factorization.
1343340151101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11481539772 (or 11481539769 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 27.
Adding to 1343340151101 its reverse (1011510433431), we get a palindrome (2354850584532).
The spelling of 1343340151101 in words is "one trillion, three hundred forty-three billion, three hundred forty million, one hundred fifty-one thousand, one hundred one".
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