Base | Representation |
---|---|
bin | 1100001101111101100011… |
… | …1000100011110101111010 |
3 | 1202120021111122210000120102 |
4 | 3003133120320203311322 |
5 | 3230100313332040442 |
6 | 44323254533355402 |
7 | 2554401036103424 |
oct | 303373070436572 |
9 | 52507448700512 |
10 | 13434001440122 |
11 | 430a36765332a |
12 | 160b723a98b62 |
13 | 765a896958a3 |
14 | 3462cdc3d814 |
15 | 1846b1116232 |
hex | c37d8e23d7a |
13434001440122 has 4 divisors (see below), whose sum is σ = 20151002160186. Its totient is φ = 6717000720060.
The previous prime is 13434001440107. The next prime is 13434001440137. The reversal of 13434001440122 is 22104410043431.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (13434001440107) and next prime (13434001440137).
It can be written as a sum of positive squares in only one way, i.e., 10434250183681 + 2999751256441 = 3230209^2 + 1731979^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3358500360029 + ... + 3358500360032.
Almost surely, 213434001440122 is an apocalyptic number.
13434001440122 is a deficient number, since it is larger than the sum of its proper divisors (6717000720064).
13434001440122 is an equidigital number, since it uses as much as digits as its factorization.
13434001440122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6717000720063.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 13434001440122 its reverse (22104410043431), we get a palindrome (35538411483553).
The spelling of 13434001440122 in words is "thirteen trillion, four hundred thirty-four billion, one million, four hundred forty thousand, one hundred twenty-two".
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