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13434001440122 = 26717000720061
BaseRepresentation
bin1100001101111101100011…
…1000100011110101111010
31202120021111122210000120102
43003133120320203311322
53230100313332040442
644323254533355402
72554401036103424
oct303373070436572
952507448700512
1013434001440122
11430a36765332a
12160b723a98b62
13765a896958a3
143462cdc3d814
151846b1116232
hexc37d8e23d7a

13434001440122 has 4 divisors (see below), whose sum is σ = 20151002160186. Its totient is φ = 6717000720060.

The previous prime is 13434001440107. The next prime is 13434001440137. The reversal of 13434001440122 is 22104410043431.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13434001440107) and next prime (13434001440137).

It can be written as a sum of positive squares in only one way, i.e., 10434250183681 + 2999751256441 = 3230209^2 + 1731979^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3358500360029 + ... + 3358500360032.

Almost surely, 213434001440122 is an apocalyptic number.

13434001440122 is a deficient number, since it is larger than the sum of its proper divisors (6717000720064).

13434001440122 is an equidigital number, since it uses as much as digits as its factorization.

13434001440122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6717000720063.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 13434001440122 its reverse (22104410043431), we get a palindrome (35538411483553).

The spelling of 13434001440122 in words is "thirteen trillion, four hundred thirty-four billion, one million, four hundred forty thousand, one hundred twenty-two".

Divisors: 1 2 6717000720061 13434001440122