Base | Representation |
---|---|
bin | 11001000001011110… |
… | …00110100011111010 |
3 | 1021200020200000202101 |
4 | 30200233012203322 |
5 | 210003113323232 |
6 | 10101015454014 |
7 | 653624065621 |
oct | 144057064372 |
9 | 37606600671 |
10 | 13434120442 |
11 | 5774235586 |
12 | 272b08730a |
13 | 13612cb8c2 |
14 | 9162926b8 |
15 | 5396051e7 |
hex | 320bc68fa |
13434120442 has 4 divisors (see below), whose sum is σ = 20151180666. Its totient is φ = 6717060220.
The previous prime is 13434120421. The next prime is 13434120509. The reversal of 13434120442 is 24402143431.
13434120442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24402143431 = 71 ⋅343692161.
It can be written as a sum of positive squares in only one way, i.e., 7096209121 + 6337911321 = 84239^2 + 79611^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 13434120442.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3358530109 + ... + 3358530112.
Almost surely, 213434120442 is an apocalyptic number.
13434120442 is a deficient number, since it is larger than the sum of its proper divisors (6717060224).
13434120442 is an equidigital number, since it uses as much as digits as its factorization.
13434120442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6717060223.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 13434120442 its reverse (24402143431), we get a palindrome (37836263873).
The spelling of 13434120442 in words is "thirteen billion, four hundred thirty-four million, one hundred twenty thousand, four hundred forty-two".
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