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1343413425021 = 3447804475007
BaseRepresentation
bin10011100011001001101…
…011100001001101111101
311202102120210100221120120
4103203021223201031331
5134002302314100041
62505053340005153
7166026015462543
oct23431153411575
94672523327516
101343413425021
11478813945a48
121984425307b9
13998b63c3305
1449043219d93
1524e2a417366
hex138c9ae137d

1343413425021 has 4 divisors (see below), whose sum is σ = 1791217900032. Its totient is φ = 895608950012.

The previous prime is 1343413425001. The next prime is 1343413425097. The reversal of 1343413425021 is 1205243143431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1343413425021 - 27 = 1343413424893 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1343413425001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223902237501 + ... + 223902237506.

It is an arithmetic number, because the mean of its divisors is an integer number (447804475008).

Almost surely, 21343413425021 is an apocalyptic number.

It is an amenable number.

1343413425021 is a deficient number, since it is larger than the sum of its proper divisors (447804475011).

1343413425021 is an equidigital number, since it uses as much as digits as its factorization.

1343413425021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 447804475010.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 1343413425021 its reverse (1205243143431), we get a palindrome (2548656568452).

The spelling of 1343413425021 in words is "one trillion, three hundred forty-three billion, four hundred thirteen million, four hundred twenty-five thousand, twenty-one".

Divisors: 1 3 447804475007 1343413425021