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134343430343 = 569236104447
BaseRepresentation
bin111110100011101111…
…1100001000011000111
3110211202121212100221022
41331013133201003013
54200113404232333
6141414433541355
712464104213403
oct1750737410307
9424677770838
10134343430343
1151a7a400691
122205341485b
13c88c9bc065
14670629a103
153764325c98
hex1f477e10c7

134343430343 has 4 divisors (see below), whose sum is σ = 134579535360. Its totient is φ = 134107325328.

The previous prime is 134343430327. The next prime is 134343430369. The reversal of 134343430343 is 343034343431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134343430343 - 24 = 134343430327 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134343439343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118051655 + ... + 118052792.

It is an arithmetic number, because the mean of its divisors is an integer number (33644883840).

Almost surely, 2134343430343 is an apocalyptic number.

134343430343 is a deficient number, since it is larger than the sum of its proper divisors (236105017).

134343430343 is an equidigital number, since it uses as much as digits as its factorization.

134343430343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 236105016.

The product of its (nonzero) digits is 186624, while the sum is 35.

Adding to 134343430343 its reverse (343034343431), we get a palindrome (477377773774).

The spelling of 134343430343 in words is "one hundred thirty-four billion, three hundred forty-three million, four hundred thirty thousand, three hundred forty-three".

Divisors: 1 569 236104447 134343430343