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134343444111 = 344781148037
BaseRepresentation
bin111110100011101111…
…1100100011010001111
3110211202121220001211020
41331013133210122033
54200113410202421
6141414434125223
712464104301502
oct1750737443217
9424677801736
10134343444111
1151a7a40aa68
1222053420813
13c88c9c53c6
1467062a1139
153764329dc6
hex1f477e468f

134343444111 has 4 divisors (see below), whose sum is σ = 179124592152. Its totient is φ = 89562296072.

The previous prime is 134343444089. The next prime is 134343444121. The reversal of 134343444111 is 111444343431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134343444111 - 215 = 134343411343 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134343444121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22390574016 + ... + 22390574021.

It is an arithmetic number, because the mean of its divisors is an integer number (44781148038).

Almost surely, 2134343444111 is an apocalyptic number.

134343444111 is a deficient number, since it is larger than the sum of its proper divisors (44781148041).

134343444111 is an equidigital number, since it uses as much as digits as its factorization.

134343444111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44781148040.

The product of its digits is 27648, while the sum is 33.

Adding to 134343444111 its reverse (111444343431), we get a palindrome (245787787542).

The spelling of 134343444111 in words is "one hundred thirty-four billion, three hundred forty-three million, four hundred forty-four thousand, one hundred eleven".

Divisors: 1 3 44781148037 134343444111