Base | Representation |
---|---|
bin | 10011100011001011010… |
… | …010011101011100101011 |
3 | 11202102122200010221120110 |
4 | 103203023102131130223 |
5 | 134002331221113121 |
6 | 2505100142225403 |
7 | 166026464034261 |
oct | 23431322353453 |
9 | 4672580127513 |
10 | 1343440410411 |
11 | 4788280a7520 |
12 | 19844b585263 |
13 | 998bbb810b8 |
14 | 49046a42431 |
15 | 24e2c997d76 |
hex | 138cb49d72b |
1343440410411 has 16 divisors (see below), whose sum is σ = 1954120798080. Its totient is φ = 814195619520.
The previous prime is 1343440410409. The next prime is 1343440410461. The reversal of 1343440410411 is 1140140443431.
It is not a de Polignac number, because 1343440410411 - 21 = 1343440410409 is a prime.
It is a super-2 number, since 2×13434404104112 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1343440410461) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2814855 + ... + 3257343.
It is an arithmetic number, because the mean of its divisors is an integer number (122132549880).
Almost surely, 21343440410411 is an apocalyptic number.
1343440410411 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1343440410411 is a deficient number, since it is larger than the sum of its proper divisors (610680387669).
1343440410411 is a wasteful number, since it uses less digits than its factorization.
1343440410411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 534506.
The product of its (nonzero) digits is 9216, while the sum is 30.
Adding to 1343440410411 its reverse (1140140443431), we get a palindrome (2483580853842).
The spelling of 1343440410411 in words is "one trillion, three hundred forty-three billion, four hundred forty million, four hundred ten thousand, four hundred eleven".
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