Base | Representation |
---|---|
bin | 1100001101111111000100… |
… | …0000101011011001011010 |
3 | 1202120022112212110001002200 |
4 | 3003133301000223121122 |
5 | 3230102130443041102 |
6 | 44323403033311030 |
7 | 2554414052510655 |
oct | 303376100533132 |
9 | 52508485401080 |
10 | 13434406221402 |
11 | 430a555094511 |
12 | 160b817565476 |
13 | 765b224bc53a |
14 | 34632b8ca89c |
15 | 1846d692151c |
hex | c37f102b65a |
13434406221402 has 12 divisors (see below), whose sum is σ = 29107880146410. Its totient is φ = 4478135407128.
The previous prime is 13434406221391. The next prime is 13434406221427. The reversal of 13434406221402 is 20412260443431.
13434406221402 is a `hidden beast` number, since 1 + 3 + 4 + 34 + 406 + 2 + 214 + 0 + 2 = 666.
13434406221402 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in only one way, i.e., 13367791127601 + 66615093801 = 3656199^2 + 258099^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 373177950577 + ... + 373177950612.
Almost surely, 213434406221402 is an apocalyptic number.
13434406221402 is an abundant number, since it is smaller than the sum of its proper divisors (15673473925008).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13434406221402 is a wasteful number, since it uses less digits than its factorization.
13434406221402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 746355901197 (or 746355901194 counting only the distinct ones).
The product of its (nonzero) digits is 110592, while the sum is 36.
Adding to 13434406221402 its reverse (20412260443431), we get a palindrome (33846666664833).
The spelling of 13434406221402 in words is "thirteen trillion, four hundred thirty-four billion, four hundred six million, two hundred twenty-one thousand, four hundred two".
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