Base | Representation |
---|---|
bin | 10011100011001011011… |
… | …101101011100111010111 |
3 | 11202102122212200101201001 |
4 | 103203023131223213113 |
5 | 134002332444231043 |
6 | 2505100325244131 |
7 | 166026531035353 |
oct | 23431335534727 |
9 | 4672585611631 |
10 | 1343443352023 |
11 | 478829826603 |
12 | 198450563647 |
13 | 998bc670cb6 |
14 | 490471aa463 |
15 | 24e2cd7974d |
hex | 138cb76b9d7 |
1343443352023 has 4 divisors (see below), whose sum is σ = 1348670758320. Its totient is φ = 1338215945728.
The previous prime is 1343443352021. The next prime is 1343443352039. The reversal of 1343443352023 is 3202533443431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1343443352023 - 21 = 1343443352021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1343443352021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2613702763 + ... + 2613703276.
It is an arithmetic number, because the mean of its divisors is an integer number (337167689580).
Almost surely, 21343443352023 is an apocalyptic number.
1343443352023 is a deficient number, since it is larger than the sum of its proper divisors (5227406297).
1343443352023 is an equidigital number, since it uses as much as digits as its factorization.
1343443352023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5227406296.
The product of its (nonzero) digits is 311040, while the sum is 37.
Adding to 1343443352023 its reverse (3202533443431), we get a palindrome (4545976795454).
The spelling of 1343443352023 in words is "one trillion, three hundred forty-three billion, four hundred forty-three million, three hundred fifty-two thousand, twenty-three".
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