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134351405412000 = 2535371599421493
BaseRepresentation
bin11110100011000100011111…
…110010110110111010100000
3122121200212110102222111220020
4132203010133302312322200
5120102203134241141000
61153424103353313440
740204366033346130
oct3643043762667240
9577625412874806
10134351405412000
1139899124903a67
121309a251a05880
1359c738b17416a
1425268dd890ac0
15107ebc5b6aba0
hex7a311fcb6ea0

134351405412000 has 192 divisors, whose sum is σ = 503011662177024. Its totient is φ = 30708892646400.

The previous prime is 134351405411983. The next prime is 134351405412013. The reversal of 134351405412000 is 214504153431.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 799626747 + ... + 799794746.

It is an arithmetic number, because the mean of its divisors is an integer number (2619852407172).

Almost surely, 2134351405412000 is an apocalyptic number.

134351405412000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

134351405412000 is an abundant number, since it is smaller than the sum of its proper divisors (368660256765024).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134351405412000 is a wasteful number, since it uses less digits than its factorization.

134351405412000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1599421528 (or 1599421510 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 134351405412000 its reverse (214504153431), we get a palindrome (134565909565431).

The spelling of 134351405412000 in words is "one hundred thirty-four trillion, three hundred fifty-one billion, four hundred five million, four hundred twelve thousand".