13435451041 has 4 divisors (see below), whose sum is σ = 13561016112. Its totient is φ = 13309885972.

The previous prime is 13435451021. The next prime is 13435451053. The reversal of 13435451041 is 14015453431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13435451041 - 2⁵ = 13435451009 is a prime.

It is a super-2 number, since 2×13435451041² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13435450994 and 13435451012.

It is not an unprimeable number, because it can be changed into a prime (13435451021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62782375 + ... + 62782588.

It is an arithmetic number, because the mean of its divisors is an integer number (3390254028).

Almost surely, 2^13435451041 is an apocalyptic number.

It is an amenable number.

13435451041 is a deficient number, since it is larger than the sum of its proper divisors (125565071).

13435451041 is a wasteful number, since it uses less digits than its factorization.

13435451041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 125565070.

The product of its (nonzero) digits is 14400, while the sum is 31.

The spelling of 13435451041 in words is "thirteen billion, four hundred thirty-five million, four hundred fifty-one thousand, forty-one".