Base | Representation |
---|---|
bin | 11001000001101000… |
… | …01011011010101101 |
3 | 1021200100011122000021 |
4 | 30200310023122231 |
5 | 210003433413203 |
6 | 10101104202141 |
7 | 653641310143 |
oct | 144064133255 |
9 | 37610148007 |
10 | 13435451053 |
11 | 5774a64262 |
12 | 272b609351 |
13 | 136167644b |
14 | 91651b593 |
15 | 5397b95bd |
hex | 320d0b6ad |
13435451053 has 2 divisors, whose sum is σ = 13435451054. Its totient is φ = 13435451052.
The previous prime is 13435451021. The next prime is 13435451059. The reversal of 13435451053 is 35015453431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7611166564 + 5824284489 = 87242^2 + 76317^2 .
It is a cyclic number.
It is not a de Polignac number, because 13435451053 - 25 = 13435451021 is a prime.
It is a super-2 number, since 2×134354510532 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13435451059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717725526 + 6717725527.
It is an arithmetic number, because the mean of its divisors is an integer number (6717725527).
Almost surely, 213435451053 is an apocalyptic number.
It is an amenable number.
13435451053 is a deficient number, since it is larger than the sum of its proper divisors (1).
13435451053 is an equidigital number, since it uses as much as digits as its factorization.
13435451053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 34.
The spelling of 13435451053 in words is "thirteen billion, four hundred thirty-five million, four hundred fifty-one thousand, fifty-three".
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