Base | Representation |
---|---|
bin | 111110100101001101… |
… | …1000110100110000010 |
3 | 110211220001101200222001 |
4 | 1331022123012212002 |
5 | 4200214001330213 |
6 | 141423351534214 |
7 | 12465242203045 |
oct | 1751233064602 |
9 | 424801350861 |
10 | 134392605058 |
11 | 51aa5138348 |
12 | 2206798a36a |
13 | c899c4891a |
14 | 670ca1ac5c |
15 | 37687db1dd |
hex | 1f4a6c6982 |
134392605058 has 4 divisors (see below), whose sum is σ = 201588907590. Its totient is φ = 67196302528.
The previous prime is 134392605023. The next prime is 134392605073. The reversal of 134392605058 is 850506293431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 850506293431 = 23 ⋅36978534497.
It can be written as a sum of positive squares in only one way, i.e., 86708458369 + 47684146689 = 294463^2 + 218367^2 .
It is a super-2 number, since 2×1343926050582 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134392604999 and 134392605017.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33598151263 + ... + 33598151266.
Almost surely, 2134392605058 is an apocalyptic number.
134392605058 is a deficient number, since it is larger than the sum of its proper divisors (67196302532).
134392605058 is an equidigital number, since it uses as much as digits as its factorization.
134392605058 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67196302531.
The product of its (nonzero) digits is 777600, while the sum is 46.
Adding to 134392605058 its reverse (850506293431), we get a palindrome (984898898489).
The spelling of 134392605058 in words is "one hundred thirty-four billion, three hundred ninety-two million, six hundred five thousand, fifty-eight".
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