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1343957906720 = 2551113437271879
BaseRepresentation
bin10011100011101010001…
…000100011010100100000
311202110222201220111001102
4103203222020203110200
5134004411211003340
62505223350053532
7166045346502002
oct23435210432440
94673881814042
101343957906720
11478a73224120
1219857494a2a8
1399972150b30
1449095670372
1524e5d11a215
hex138ea223520

1343957906720 has 384 divisors, whose sum is σ = 3824221040640. Its totient is φ = 439787335680.

The previous prime is 1343957906717. The next prime is 1343957906743. The reversal of 1343957906720 is 276097593431.

It is a super-3 number, since 3×13439579067203 (a number of 37 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 715250741 + ... + 715252619.

It is an arithmetic number, because the mean of its divisors is an integer number (9958908960).

Almost surely, 21343957906720 is an apocalyptic number.

1343957906720 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1343957906720, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1912110520320).

1343957906720 is an abundant number, since it is smaller than the sum of its proper divisors (2480263133920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1343957906720 is a wasteful number, since it uses less digits than its factorization.

1343957906720 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2688 (or 2680 counting only the distinct ones).

The product of its (nonzero) digits is 8573040, while the sum is 56.

The spelling of 1343957906720 in words is "one trillion, three hundred forty-three billion, nine hundred fifty-seven million, nine hundred six thousand, seven hundred twenty".