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1344003123121 = 3742787848959
BaseRepresentation
bin10011100011101100110…
…101000010011110110001
311202111002212222201021221
4103203230311002132301
5134010004244414441
62505232043145041
7166046436024151
oct23435465023661
94674085881257
101344003123121
11478a967a794a
12198587b15181
139997b622ab9
144909b680761
1524e6209c8d1
hex138ecd427b1

1344003123121 has 8 divisors (see below), whose sum is σ = 1380361418240. Its totient is φ = 1307646611568.

The previous prime is 1344003123107. The next prime is 1344003123191. The reversal of 1344003123121 is 1213213004431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1344003123121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1344003123191) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1158640 + ... + 2007598.

It is an arithmetic number, because the mean of its divisors is an integer number (172545177280).

Almost surely, 21344003123121 is an apocalyptic number.

It is an amenable number.

1344003123121 is a deficient number, since it is larger than the sum of its proper divisors (36358295119).

1344003123121 is an equidigital number, since it uses as much as digits as its factorization.

1344003123121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 891783.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1344003123121 its reverse (1213213004431), we get a palindrome (2557216127552).

The spelling of 1344003123121 in words is "one trillion, three hundred forty-four billion, three million, one hundred twenty-three thousand, one hundred twenty-one".

Divisors: 1 37 42787 848959 1583119 31411483 36324408733 1344003123121