Base | Representation |
---|---|
bin | 11110100011110010110010… |
… | …000101010000101101010011 |
3 | 122121212121202001022011010221 |
4 | 132203302302011100231103 |
5 | 120104011430203200120 |
6 | 1153503003122133511 |
7 | 40211105441350165 |
oct | 3643626205205523 |
9 | 577777661264127 |
10 | 134401104350035 |
11 | 39908208637776 |
12 | 130a7a01ab1297 |
13 | 59cbc7b7338c3 |
14 | 2529096212935 |
15 | 1081133d920aa |
hex | 7a3cb2150b53 |
134401104350035 has 16 divisors (see below), whose sum is σ = 162554683686912. Its totient is φ = 106672013532000.
The previous prime is 134401104349999. The next prime is 134401104350063. The reversal of 134401104350035 is 530053401104431.
It is not a de Polignac number, because 134401104350035 - 213 = 134401104341843 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28241890 + ... + 32655880.
It is an arithmetic number, because the mean of its divisors is an integer number (10159667730432).
Almost surely, 2134401104350035 is an apocalyptic number.
134401104350035 is a deficient number, since it is larger than the sum of its proper divisors (28153579336877).
134401104350035 is a wasteful number, since it uses less digits than its factorization.
134401104350035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4462074.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 134401104350035 its reverse (530053401104431), we get a palindrome (664454505454466).
The spelling of 134401104350035 in words is "one hundred thirty-four trillion, four hundred one billion, one hundred four million, three hundred fifty thousand, thirty-five".
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