1344012413 has 4 divisors (see below), whose sum is σ = 1344110460. Its totient is φ = 1343914368.

The previous prime is 1344012391. The next prime is 1344012419. The reversal of 1344012413 is 3142104431.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3142104431 = 11813 ⋅265987.

It can be written as a sum of positive squares in 2 ways, for example, as 180042724 + 1163969689 = 13418^2 + 34117^2 .

It is a cyclic number.

It is not a de Polignac number, because 1344012413 - 2¹⁸ = 1343750269 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344012419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24308 + ... + 57261.

It is an arithmetic number, because the mean of its divisors is an integer number (336027615).

Almost surely, 2^1344012413 is an apocalyptic number.

It is an amenable number.

1344012413 is a deficient number, since it is larger than the sum of its proper divisors (98047).

1344012413 is an equidigital number, since it uses as much as digits as its factorization.

1344012413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 98046.

The product of its (nonzero) digits is 1152, while the sum is 23.

The square root of 1344012413 is about 36660.7748554228. The cubic root of 1344012413 is about 1103.5730680148.

Adding to 1344012413 its reverse (3142104431), we get a palindrome (4486116844).

The spelling of 1344012413 in words is "one billion, three hundred forty-four million, twelve thousand, four hundred thirteen".