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134402204041 = 734695534827
BaseRepresentation
bin111110100101011111…
…1101110000110001001
3110211220201110101021221
41331022333232012021
54200223431012131
6141424333402041
712465416612320
oct1751277560611
9424821411257
10134402204041
1151aaa5a4196
122206b039321
13c89bc29ab1
14670ddd90b7
153769585411
hex1f4afee189

134402204041 has 8 divisors (see below), whose sum is σ = 153646825280. Its totient is φ = 115168659408.

The previous prime is 134402204033. The next prime is 134402204063. The reversal of 134402204041 is 140402204431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 134402204041 - 23 = 134402204033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134402203997 and 134402204015.

It is not an unprimeable number, because it can be changed into a prime (134402204021) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2743131 + ... + 2791696.

It is an arithmetic number, because the mean of its divisors is an integer number (19205853160).

Almost surely, 2134402204041 is an apocalyptic number.

It is an amenable number.

134402204041 is a deficient number, since it is larger than the sum of its proper divisors (19244621239).

134402204041 is an equidigital number, since it uses as much as digits as its factorization.

134402204041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5538303.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 134402204041 its reverse (140402204431), we get a palindrome (274804408472).

The spelling of 134402204041 in words is "one hundred thirty-four billion, four hundred two million, two hundred four thousand, forty-one".

Divisors: 1 7 3469 24283 5534827 38743789 19200314863 134402204041